Same way as you would in JavaScript. delete myArray[key]; Note that this sets the element to undefined. Better to use the Array.prototype.splice function: const index = myArray.indexOf(key, 0); if (index > -1) { myArray.splice(index, 1); }
This approach has the advantage of not needing to loop over all the elements (at least not explicitly). But since array_to_string_internal() in array.c still loops over array elements and concatenates them into a string, it’s probably not more efficient than the looping solutions proposed, but it’s more readable. if [[ ” ${array[*]} ” =~ ” … Read more
IFS=’, ‘ read -r -a array <<< “$string” Note that the characters in $IFS are treated individually as separators so that in this case fields may be separated by either a comma or a space rather than the sequence of the two characters. Interestingly though, empty fields aren’t created when comma-space appears in the input … Read more
Yes. As of Swift 3.0, if you need the index for each element along with its value, you can use the enumerated() method to iterate over the array. It returns a sequence of pairs composed of the index and the value for each item in the array. For example: for (index, element) in list.enumerated() { … Read more
Here’s a summary of Dimitris Andreou’s link. Remember sum of i-th powers, where i=1,2,..,k. This reduces the problem to solving the system of equations a1 + a2 + … + ak = b1 a12 + a22 + … + ak2 = b2 … a1k + a2k + … + akk = bk Using Newton’s identities, … Read more
You can use it like this: ## declare an array variable declare -a arr=(“element1” “element2” “element3”) ## now loop through the above array for i in “${arr[@]}” do echo “$i” # or do whatever with individual element of the array done # You can access them using echo “${arr[0]}”, “${arr[1]}” also Also works for multi-line … Read more