May be too late, but for upcoming searchers, possible solution could be:
select sex, employed, COUNT(*) / CAST( SUM(count(*)) over (partition by sex) as float)
from my_table
group by sex, employed
By IO Statistics this seems to be most effective solution – may be dependant on number of rows to be queried – tested on numbers above …
The same attitude could be used for getting male / female percentage:
select sex, COUNT(*) / CAST( SUM(count(*)) over () as float)
from my_table
group by sex
Regards,
Jan