Does [=] imply that all local variables will be copied?

No. It just means that all local variables from the ambient scope are available for lookup inside the body of the lambda. Only if you refer to a name of an ambient local variable will that variable be captured, and it’ll be captured by value.

The “capture anything” shorthands = and & are just syntactic sugar, essentially, telling the compiler to “figure out what I mean”.


A formal reference from 5.1.2/11-12:

If a lambda-expression has an associated capture-default and its compound-statement odr-uses […] a variable with automatic storage duration and the odr-used entity is not explicitly captured, then the odr-used entity is said to be implicitly captured […]

An entity is captured if it is captured explicitly or implicitly.

Note that “capture-default” refers to [=] and [&]. To repeat, specifying a capture-default doesn’t capture anything; only odr-using a variable does.

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