How do I get the name of the class containing a logging call in Python?

For a rather easy, pythonic way to get the class name to output with your logger, simply use a logging class.

import logging


# Create a base class
class LoggingHandler:
    def __init__(self, *args, **kwargs):
        self.log = logging.getLogger(self.__class__.__name__)


# Create test class A that inherits the base class
class testclassa(LoggingHandler):
    def testmethod1(self):
        # call self.log.<log level> instead of logging.log.<log level>
        self.log.error("error from test class A")


# Create test class B that inherits the base class
class testclassb(LoggingHandler):
    def testmethod2(self):
        # call self.log.<log level> instead of logging.log.<log level>
        self.log.error("error from test class B")


testclassa().testmethod1()
testclassb().testmethod2()

By naming the logger as above, the %(name)s will be the name of your class

example output

$ python mymodule.py
[2016-02-03 07:12:25,624] ERROR [testclassa.testmethod1:29] error from test class A
[2016-02-03 07:12:25,624] ERROR [testclassb.testmethod2:36] error from test class B

Alternative(s)

Non-inheritance

import logging


def log(className):
    return logging.getLogger(className)


class testclassa:
    def testmethod1(self):
        log(self.__class__.__name__).error("error from test class A")


class testclassb:
    def testmethod2(self):
        log(self.__class__.__name__).error("error from test class B")


testclassa().testmethod1()
testclassb().testmethod2()