My version using drop:
every n xs = case drop (n-1) xs of
y : ys -> y : every n ys
[] -> []
Edit: this also works for finite lists. For infinite lists only, Charles Stewart’s solution is slightly shorter.
My version using drop:
every n xs = case drop (n-1) xs of
y : ys -> y : every n ys
[] -> []
Edit: this also works for finite lists. For infinite lists only, Charles Stewart’s solution is slightly shorter.