array<T>::size()
is constexpr
, but you can’t use it in this way because a1
isn’t a constexpr
value. Additionally, it can’t be constexpr
because string
isn’t a literal type.
However, you can work around this if you want, by deducing the size_t
template parameter. Example:
#include <string>
#include <array>
#include <iostream>
using namespace std;
template<typename>
struct array_size;
template<typename T, size_t N>
struct array_size<array<T,N> > {
static size_t const size = N;
};
array<string, 42> a1;
array<string, array_size<decltype(a1)>::size> a2;
int main() {
cout << a2.size() << endl;
}