You can group your data in one go assuming there are only distinct Foo
:
Map<String, Map<String, Foo>> map = list.stream()
.collect(Collectors.groupingBy(f -> f.b.id,
Collectors.toMap(f -> f.b.date, Function.identity())));
Saving some characters by using static imports:
Map<String, Map<String, Foo>> map = list.stream()
.collect(groupingBy(f -> f.b.id, toMap(f -> f.b.date, identity())));