Yes it does, it works exactly as documented.
._replace returns a new namedtuple, it does not modify the original, so you need to write this:
p = p._replace(x=33)
See here: somenamedtuple._replace(kwargs) for more information.
Yes it does, it works exactly as documented.
._replace returns a new namedtuple, it does not modify the original, so you need to write this:
p = p._replace(x=33)
See here: somenamedtuple._replace(kwargs) for more information.