If you read the Keras documentation entry for Dense
, you will see that this call:
Dense(16, input_shape=(5,3))
would result in a Dense
network with 3 inputs and 16 outputs which would be applied independently for each of 5 steps. So, if D(x)
transforms 3 dimensional vector to 16-d vector, what you’ll get as output from your layer would be a sequence of vectors: [D(x[0,:]), D(x[1,:]),..., D(x[4,:])]
with shape (5, 16)
. In order to have the behavior you specify you may first Flatten
your input to a 15-d vector and then apply Dense
:
model = Sequential()
model.add(Flatten(input_shape=(3, 2)))
model.add(Dense(16))
model.add(Activation('relu'))
model.add(Dense(4))
model.compile(loss="mean_squared_error", optimizer="SGD")
EDIT:
As some people struggled to understand – here you have an explaining image: