Thanks – both good answers. I went with the client side script “pageloaded” in the end. That is a fairly buried method that google did not reveal to me. For those who are interested, this code works with FireBug to give a good demo of the PageLoaded method working to find the updated panels: <script … Read more
I had an issue using this in a user control (in a page this worked fine); the Button1 is inside an updatepanel, and the scriptmanager is on the usercontrol. protected void Button1_Click(object sender, EventArgs e) { string scriptstring = “alert(‘Welcome’);”; ScriptManager.RegisterStartupScript(this, this.GetType(), “alertscript”, scriptstring, true); } Now it seems you have to be careful with … Read more
You can use code as below when using Image as Loading <asp:UpdateProgress id=”updateProgress” runat=”server”> <ProgressTemplate> <div style=”position: fixed; text-align: center; height: 100%; width: 100%; top: 0; right: 0; left: 0; z-index: 9999999; background-color: #000000; opacity: 0.7;”> <asp:Image ID=”imgUpdateProgress” runat=”server” ImageUrl=”~/images/ajax-loader.gif” AlternateText=”Loading …” ToolTip=”Loading …” style=”padding: 10px;position:fixed;top:45%;left:50%;” /> </div> </ProgressTemplate> </asp:UpdateProgress> using Text as Loading <asp:UpdateProgress … Read more
You need to register each and every LinkButton as an AsyncPostBackTrigger. After each row is bound in your GridView, you’ll need to search for the LinkButton and register it through code-behind as follows: protected void OrderGrid_RowDataBound(object sender, GridViewRowEventArgs e) { LinkButton lb = e.Row.FindControl(“MarkAsCompleteButton”) as LinkButton; ScriptManager.GetCurrent(this).RegisterAsyncPostBackControl(lb); } This also requires that ClientIDMode=”AutoID” be set … Read more
Here is a complete solution Entire form tag of the asp.net page <form id=”form1″ runat=”server”> <asp:LinkButton ID=”LinkButton1″ runat=”server” /> <%– included to force __doPostBack javascript function to be rendered –%> <input type=”button” id=”Button45″ name=”Button45″ onclick=”javascript:__doPostBack(‘ButtonA’,”)” value=”clicking this will run ButtonA.Click Event Handler” /><br /><br /> <input type=”button” id=”Button46″ name=”Button46″ onclick=”javascript:__doPostBack(‘ButtonB’,”)” value=”clicking this will run ButtonB.Click … Read more
Aspx <ajax:ModalPopupExtender runat=”server” ID=”modalPop” PopupControlID=”pnlpopup” TargetControlID=”btnGo” BackgroundCssClass=”modalBackground” DropShadow=”true” CancelControlID=”btnCancel” X=”470″ Y=”300″ /> //Codebehind protected void OkButton_Clicked(object sender, EventArgs e) { modalPop.Hide(); //Do something in codebehind } And don’t set the OK button as OkControlID.
When you use an UpdatePanel, then you can not call JavaScript using ClientScript as you have tried to. You have to use ScriptManager.RegisterStartupScript instead. So change your Page.ClientScript.RegisterStartupScript(this.GetType(), “myKey”, javaScript); to ScriptManager.RegisterStartupScript(updatePanelId,updatePanelId.GetType(), “alert”, javaScript, true);
There is a property on the ScriptManager which allows you to set the time-out in seconds. The default value is 90 seconds. AsyncPostBackTimeout=”300″
Most simple way is to use MSAjax pageLoad Event in your javascript code : <script> ///<summary> /// This will fire on initial page load, /// and all subsequent partial page updates made /// by any update panel on the page ///</summary> function pageLoad(){ alert(‘page loaded!’) } </script> I have used it many times, it works … Read more
Instead of putting your jQuery code inside of $(document).ready(), put it inside function pageLoad(sender, args) { … } pageLoad is executed after every postback, synchronous or asynchronous. pageLoad is a reserved function name in ASP.NET AJAX that is for this purpose. $(document).ready() on the other hand, is executed only once, when the DOM is initially … Read more