Use this code, iconClick is bool variable, or you need other condition check it, var iconClick = true eye Action method: @IBAction func iconAction(sender: AnyObject) { if iconClick { passwordTF.secureTextEntry = false } else { passwordTF.secureTextEntry = true } iconClick = !iconClick } hope its helpful
Thats what did the trick for me: [self.titleField setSelectedTextRange:[self.titleField textRangeFromPosition:self.titleField.beginningOfDocument toPosition:self.titleField.endOfDocument]]; Pretty ugly but it works, so there will be no sharedMenuController shown! To fix the “only works every second time” problem use following: __weak typeof(self) weakSelf = self; dispatch_async(dispatch_get_main_queue(), ^{ __strong __typeof(weakSelf) strongSelf = weakSelf; UITextRange *range = [strongSelf textRangeFromPosition:strongSelf.beginningOfDocument toPosition:strongSelf.endOfDocument]; [strongSelf setSelectedTextRange:range]; }); … Read more
If you’re using Swift, go read my port of this answer for Swift 4 and use that instead. If you’re in Objective-C… Firstly, to your UITextFieldDelegate, add these instance variables… NSString *previousTextFieldContent; UITextRange *previousSelection; … and these methods: // Version 1.3 // Source and explanation: http://stackoverflow.com/a/19161529/1709587 -(void)reformatAsCardNumber:(UITextField *)textField { // In order to make the … Read more
This is the quickest way I’ve found without doing any subclasses: UIView *spacerView = [[UIView alloc] initWithFrame:CGRectMake(0, 0, 10, 10)]; [textfield setLeftViewMode:UITextFieldViewModeAlways]; [textfield setLeftView:spacerView]; In Swift: let spacerView = UIView(frame:CGRect(x:0, y:0, width:10, height:10)) textField.leftViewMode = UITextFieldViewMode.Always textField.leftView = spacerView Swift 5: let spacerView = UIView(frame:CGRect(x:0, y:0, width:10, height:10)) textField.leftViewMode = .always textField.leftView = spacerView
You can do it in a few lines like this: BOOL valid; NSCharacterSet *alphaNums = [NSCharacterSet decimalDigitCharacterSet]; NSCharacterSet *inStringSet = [NSCharacterSet characterSetWithCharactersInString:myInputField.text]; valid = [alphaNums isSupersetOfSet:inStringSet]; if (!valid) // Not numeric — this is for validating input is numeric chars only. Look at the documentation for NSCharacterSet for the other options. You can use characterSetWithCharactersInString … Read more
The much safer approach is to use a UIToolBar with Done Button as inputAccessoryView. Sample Code : UIToolbar *keyboardDoneButtonView = [[UIToolbar alloc] init]; [keyboardDoneButtonView sizeToFit]; UIBarButtonItem *doneButton = [[UIBarButtonItem alloc] initWithTitle:@”Done” style:UIBarButtonItemStyleBordered target:self action:@selector(doneClicked:)]; [keyboardDoneButtonView setItems:[NSArray arrayWithObjects:doneButton, nil]]; txtField.inputAccessoryView = keyboardDoneButtonView; Your -doneClicked method should look like this : – (IBAction)doneClicked:(id)sender { NSLog(@”Done Clicked.”); [self.view … Read more
This is how you might handle the problem on a SSN verification field, you can modify the max length and remove the if statement checking for keyboard type if you need to. There is also logic to suppress the max length alerts when the user is typing as opposed to pasting data. Within the context … Read more
I wrote an extension method to do this for me and it’s pretty fast: extension XCUIElement { /** Removes any current text in the field before typing in the new value – Parameter text: the text to enter into the field */ func clearAndEnterText(text: String) { guard let stringValue = self.value as? String else { … Read more
Solution for swift 3.0 and above func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool { let allowedCharacters = CharacterSet.decimalDigits let characterSet = CharacterSet(charactersIn: string) return allowedCharacters.isSuperset(of: characterSet) }
I don’t really understand your question, but I’m guessing you want a UITextField which displays dots for the characters, which every password field on the iPhone does. For this, you want to set the secureTextEntry property of that UITextField (UITextField has such a property because it conforms to the UITextInputTraits protocol) to YES: textfield.secureTextEntry = … Read more