show() is just a convenience function for setVisible(true). Similarly hide() is equivalent to setVisible(false) Internally, the same code is used to render your view. See http://doc.qt.io/archives/qt-4.7/qwidget.html#show as an example. According to it, void QWidget::show () [slot] Shows the widget and its child widgets. This function is equivalent to setVisible(true). You’ll find lots of such functions … Read more
The instance declaration you made is the correct way to go. It seems you forgot to remove that faulty deriving clause from the original data declaration. data Operace = Op (Int->Int->Int) String (Int->Int->Int) instance Show Operace where show (Op op str inv) = show str
Use JQuery. You need to set-up a click event on your button which will toggle the visibility of your wizard div. $(‘#btn’).click(function() { $(‘#wizard’).toggle(); }); Refer to the JQuery website for more information. This can also be done without JQuery. Using only standard JavaScript: <script type=”text/javascript”> function toggle_visibility(id) { var e = document.getElementById(id); if(e.style.display == … Read more
Use media queries. Your CSS code would be: @media screen and (max-width: 1024px) { .yourClass { display: none !important; } }
I do a similar thing, however I hide the select2 container which is always the next node over from the start point so it would look like. $(document).on(‘change’, ‘.country’, function () { if ($(this).val() == $(this).data(‘current-countryCode’)) { $(‘#states’).next(“.select2-container”).show(); } else { $(‘#states’).next(“.select2-container”).hide(); } }); So I have been taking the same approach you have
You need to hide the children and not the containing div. $(“#navSub”).children().hide(); So now if the div you are trying to show is an element in the parent div it will still show while the others stay hidden.
I wouldn’t use checkboxes, i’d use the code you already have DEMO http://jsfiddle.net/6W7XD/1/ CSS body { display: block; } .span3:focus ~ .alert { display: none; } .span2:focus ~ .alert { display: block; } .alert{display:none;} HTML <span class=”span3″>Hide Me</span> <span class=”span2″>Show Me</span> <p class=”alert” >Some alarming information here</p> This way the text is only hidden on … Read more
When the activity launches It seems that the keyboard is initially displayed but hidden by something else, because the following works (but is actually a dirty work-around): First Method InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE); editText.postDelayed(new Runnable() { @Override public void run() { editText.requestFocus(); imm.showSoftInput(editText, 0); } }, 100); Second method in onCreate to launch it … Read more
Use if( $(“#test”).css(‘display’) == ‘block’) { I’m fairly sure .css(), returning a calculated value, will always return a lower case result – the docs say nothing on this. To make totally sure, you could do a if( $(“#test”).css(‘display’).toLowerCase() == ‘block’) { while you can rely on display giving reliable results, note that some CSS properties … Read more
You can use .is(‘:visible’) to test if something is visible and .is(‘:hidden’) to test for the opposite: $(‘#offers’).toggle(!$(‘#column-left form’).is(‘:visible’)); // or: $(‘#offers’).toggle($(‘#column-left form’).is(‘:hidden’)); Reference: http://api.jquery.com/is/ http://api.jquery.com/visible-selector/ http://api.jquery.com/hidden-selector/