Direct assignment: NSTimeInterval interval = 1002343.5432542; NSInteger time = interval; //time is now equal to 1002343 NSTimeInterval is a double, so if you assign it directly to a NSInteger (or int, if you wish) it’ll work. This will cut off the time to the nearest second. If you wish to round to the nearest second … Read more
Since iOS 8.0 there is now NSDateComponentsFormatter which has a stringFromTimeInterval: method. [[NSDateComponentsFormatter new] stringFromTimeInterval:timeInterval];
since you are not using ARC, when you write startTime = [NSDate date]; you do not retain startTime, so it is deallocated before -viewWillDisappear is called. Try startTime = [[NSDate date] retain]; Also, I recommend to use ARC. There should be much less errors with memory management with it, than without it
Brief Description Just another approach to complete the answer of JBRWilkinson but adding some code. It can also offers a solution to Alex Reynolds’s comment. Use NSCalendar method: (NSDateComponents *)components:(NSUInteger)unitFlags fromDate:(NSDate *)startingDate toDate:(NSDate *)resultDate options:(NSUInteger)opts “Returns, as an NSDateComponents object using specified components, the difference between two supplied dates”. (From the API documentation). Create 2 … Read more
Swift supports remainder calculations on floating-point numbers, so we can use % 1. var ms = Int((interval % 1) * 1000) as in: func stringFromTimeInterval(interval: TimeInterval) -> NSString { let ti = NSInteger(interval) let ms = Int((interval % 1) * 1000) let seconds = ti % 60 let minutes = (ti / 60) % 60 … Read more
Brief Description The answer from Brian Ramsay is more convenient if you only want to convert to minutes. If you want Cocoa API do it for you and convert your NSTimeInterval not only to minutes but also to days, months, week, etc,… I think this is a more generic approach Use NSCalendar method: (NSDateComponents *)components:(NSUInteger)unitFlags … Read more
Your attempt to calculate elapsedTime is incorrect. In Swift 3, it would be: let elapsed = Date().timeIntervalSince(timeAtPress) Note the () after the Date reference. The Date() instantiates a new date object, and then timeIntervalSince returns the time difference between that and timeAtPress. That will return a floating point value (technically, a TimeInterval). If you want … Read more
You are needlessly complicating things. Why are you converting the date to a time interval (then the time interval to a different primitive)? Just [sharedDefaults setObject:theDate forKey:@”theDateKey”] and be done with it. NSDate is one of the “main types” supported by the PLIST format (dates, numbers, strings, data, dictionaries, and arrays), so you can just … Read more
This will work: override func viewDidLoad() { super.viewDidLoad() // Swift block syntax (iOS 10+) let timer = Timer(timeInterval: 0.4, repeats: true) { _ in print(“Done!”) } // Swift >=3 selector syntax let timer = Timer.scheduledTimer(timeInterval: 0.4, target: self, selector: #selector(self.update), userInfo: nil, repeats: true) // Swift 2.2 selector syntax let timer = NSTimer.scheduledTimerWithTimeInterval(0.4, target: self, … Read more
You can use Swift’s round function to accomplish this. To round a Double with 3 digits precision, first multiply it by 1000, round it and divide the rounded result by 1000: let x = 1.23556789 let y = Double(round(1000 * x) / 1000) print(y) /// 1.236 Unlike any kind of printf(…) or String(format: …) solutions, … Read more