In Swift 3.0 let myFloat : CGFloat = 1234.5 let myNumber = NSNumber(value: Float(myFloat)) or let myNumber = NSNumber(value: Double(myFloat)) In Swift 2 let myNumber = NSNumber(double: myFloat.native) or let myNumber = NSNumber(double: Double(myFloat)) or let myNumber = NSNumber(float: Float(myFloat))
Here’s an NSScanner based solution: // Input NSString *originalString = @”This is my string. #1234″; // Intermediate NSString *numberString; NSScanner *scanner = [NSScanner scannerWithString:originalString]; NSCharacterSet *numbers = [NSCharacterSet characterSetWithCharactersInString:@”0123456789″]; // Throw away characters before the first number. [scanner scanUpToCharactersFromSet:numbers intoString:NULL]; // Collect numbers. [scanner scanCharactersFromSet:numbers intoString:&numberString]; // Result. int number = [numberString integerValue]; (Some of … Read more
I recommend using the -[NSNumber objCType] method. It allows you to do: NSNumber * n = [NSNumber numberWithBool:YES]; if (strcmp([n objCType], @encode(BOOL)) == 0) { NSLog(@”this is a bool”); } else if (strcmp([n objCType], @encode(int)) == 0) { NSLog(@”this is an int”); } For more information on type encodings, check out the Objective-C Runtime Reference.
NSNumber is a class, not a primitive, and is used when you need to put raw numbers into dictionaries, arrays, or otherwise encapsulate them. NSInteger, NSUInteger, CGFloat, etc are simple types and correspond (on 32-bt systems like the iPhone) to int, unsigned int and float. As a general rule, if you need to store a … Read more
Swift 3.0 NSNumber(integer:myInteger) has changed to NSNumber(value:myInteger) let someString = “42222222222” if let myInteger = Int(someString) { let myNumber = NSNumber(value:myInteger) } Swift 2.0 Use the Int() initialiser like this. let someString = “42222222222” if let myInteger = Int(someString) { let myNumber = NSNumber(integer:myInteger) print(myNumber) } else { print(“‘\(someString)’ did not convert to an Int”) … Read more
You can do: NSDecimalNumber *decNum = [NSDecimalNumber decimalNumberWithDecimal:[aNumber decimalValue]];
Before Swift 3, many types were automatically “bridged” to an instance of some NSObject subclass where necessary, such as String to NSString, or Int, Float, … to NSNumber. As of Swift 3 you have to make that conversion explicit: var currentIndex = 0 for item in self.selectedFolder.arrayOfTasks { item.index = currentIndex as NSNumber // <– … Read more
You cannot cast it because NSInteger is not an object, just an alias for a built-in type. You can always create a new NSNumber object from NSInteger, like this: NSNumber *myNum = @(myNsIntValue); or in the prior version of the compiler, use NSNumber *myNum = [NSNumber numberWithInteger:myNsIntValue];
So, I found out that the class property [NSDecimalNumber notANumber] is just for this purpose. In some languages NaN != NaN, but this isn’t the case in Cocoa.
-(NSString*) suffixNumber:(NSNumber*)number { if (!number) return @””; long long num = [number longLongValue]; int s = ( (num < 0) ? -1 : (num > 0) ? 1 : 0 ); NSString* sign = (s == -1 ? @”-” : @”” ); num = llabs(num); if (num < 1000) return [NSString stringWithFormat:@”%@%lld”,sign,num]; int exp = … Read more