I would just register your handler twice. router.Path(“/articles/{id:[0-9]+}”). Queries(“key”, “{[0-9]*?}”). HandlerFunc(YourHandler). Name(“YourHandler”) router.Path(“/articles/{id:[0-9]+}”).HandlerFunc(YourHandler) Here is a working program to demonstrate. Notice that I am using r.FormValue to get the query parameter. Note: make sure you have an up to date version go get -u github.com/gorilla/mux since a bug of query params not getting added the … Read more
You can define middleware for mux router, here is an example: func main() { port := “:3000” var router = mux.NewRouter() router.Use(commonMiddleware) router.HandleFunc(“/m/{msg}”, handleMessage).Methods(“GET”) router.HandleFunc(“/n/{num}”, handleNumber).Methods(“GET”) // rest of code goes here } func commonMiddleware(next http.Handler) http.Handler { return http.HandlerFunc(func(w http.ResponseWriter, r *http.Request) { w.Header().Add(“Content-Type”, “application/json”) next.ServeHTTP(w, r) }) } Read more in the documentation
I think you might be looking for PathPrefix… func main() { r := mux.NewRouter() r.HandleFunc(“/search/{searchTerm}”, Search) r.HandleFunc(“/load/{dataId}”, Load) r.PathPrefix(“https://stackoverflow.com/”).Handler(http.FileServer(http.Dir(“./static/”))) http.ListenAndServe(“:8100”, r) }