Get coefficients estimated by maximum likelihood into a stargazer table

I was just having this problem and overcame this through the use of the coef se, and omit functions within stargazer… e.g. stargazer(regressions, … coef = list(… list of coefs…), se = list(… list of standard errors…), omit = c(sequence), covariate.labels = c(“new names”), dep.var.labels.include = FALSE, notes.append=FALSE), file=””)

Extract regression coefficient values

A summary.lm object stores these values in a matrix called ‘coefficients’. So the value you are after can be accessed with: a2Pval <- summary(mg)$coefficients[2, 4] Or, more generally/readably, coef(summary(mg))[“a2″,”Pr(>|t|)”]. See here for why this method is preferred.

How do I extract just the number from a named number (without the name)?

For a single element like this, use [[ rather than [. Compare: coefficients(out)[“newx”] # newx # 1 coefficients(out)[[“newx”]] # [1] 1 More generally, use unname(): unname(coefficients(out)[c(“newx”, “(Intercept)”)]) # [1] 1.0 1.5 head(unname(mtcars)) # NA NA NA NA NA NA NA NA NA NA NA # Mazda RX4 21.0 6 160 110 3.90 2.620 16.46 0 … Read more

Linear Regression and group by in R

Since 2009, dplyr has been released which actually provides a very nice way to do this kind of grouping, closely resembling what SAS does. library(dplyr) d <- data.frame(state=rep(c(‘NY’, ‘CA’), c(10, 10)), year=rep(1:10, 2), response=c(rnorm(10), rnorm(10))) fitted_models = d %>% group_by(state) %>% do(model = lm(response ~ year, data = .)) # Source: local data frame [2 … Read more

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