Here’s something slimmer, although it doesn’t avoid repeating the list of fields. It uses “parameter destructuring” to avoid the need for the v parameter. ({id, title}) => ({id, title}) (See a runnable example in this other answer). @EthanBrown’s solution is more general. Here is a more idiomatic version of it which uses Object.assign, and computed … Read more
While ugly and a bit repetitive, you can do ({x: oof.x, y: oof.y} = foo); which will read the two values of the foo object, and write them to their respective locations on the oof object. Personally I’d still rather read oof.x = foo.x; oof.y = foo.y; or [‘x’, ‘y’].forEach(prop => oof[prop] = foo[prop]); though.
It turns out it’s possible to specify the type after : for the whole destructuring pattern: const {foo}: {foo: IFoo[]} = bar; Which in reality is not any better than plain old const foo: IFoo[] = bar.foo;