a is of type [i32; 3]; an array of three i32s. [i32; 3] does not implement an iter method, but it does dereference into &[i32]. &[i32] implements an iter method which produces an iterator. This iterator implements Iterator<Item=&i32>. It uses &i32 rather than i32 because the iterator has to work on arrays of any type, … Read more
You can use the AsRef<str> trait: // will accept any object that implements AsRef<str> fn print<S: AsRef<str>>(stringlike: S) { // call as_ref() to get a &str let str_ref = stringlike.as_ref(); println!(“got: {:?}”, str_ref) } fn main() { let a: &str = “str”; let b: String = String::from(“String”); let c: &String = &b; print(a); print(c); print(b); … Read more
The scope of b is the new function, so its memory will be freed when the function returns. But you are trying to return a reference to b from that function. If Rust let you do this, the only code that could possibly use that reference would use it after the value is invalid. The … Read more