How to print last two columns using awk
You can make use of variable NF which is set to the total number of fields in the input record: awk ‘{print $(NF-1),”\t”,$NF}’ file this assumes that you have at least 2 fields.
You can make use of variable NF which is set to the total number of fields in the input record: awk ‘{print $(NF-1),”\t”,$NF}’ file this assumes that you have at least 2 fields.
If you quickly learn the basics of awk, you can indeed do amazing things on the command line. But the real reason to learn awk is to have an excuse to read the superb book The AWK Programming Language by Aho, Kernighan, and Weinberger. The AWK Programming Language at archive.org You would think, from the … Read more
awk ‘{for(i=1;i<4;i++) $i=””;print}’ file
If you’re looking for a particular string, put quotes around it: awk ‘$1 == “findtext” {print $3}’ Otherwise, awk will assume it’s a variable name.
The shebang line has never been specified as part of POSIX, SUS, LSB or any other specification. AFAIK, it hasn’t even been properly documented. There is a rough consensus about what it does: take everything between the ! and the \n and exec it. The assumption is that everything between the ! and the \n … Read more
$1=”” leaves a space as Ben Jackson mentioned, so use a for loop: awk ‘{for (i=2; i<=NF; i++) print $i}’ filename So if your string was “one two three”, the output will be: two three If you want the result in one row, you could do as follows: awk ‘{for (i=2; i<NF; i++) printf $i … Read more
This maybe what you’re looking for: awk ‘BEGIN {FS=” “;} {printf “‘\”%s’\” “, $1}’ That is, with ‘\” you close the opening ‘, then print a literal ‘ by escaping it and finally open the ‘ again.
Use the fact that awk splits the lines in fields based on a field separator, that you can define. Hence, defining the field separator to / you can say: awk -F “https://stackoverflow.com/” ‘{print $NF}’ input as NF refers to the number of fields of the current record, printing $NF means printing the last one. So … Read more
I’ll have a go at this. To delete 5 lines after a pattern (including the line with the pattern): sed -e ‘/pattern/,+5d’ file.txt To delete 5 lines after a pattern (excluding the line with the pattern): sed -e ‘/pattern/{n;N;N;N;N;d}’ file.txt
This is the very basic awk ‘/pattern/{ print $0 }’ file ask awk to search for pattern using //, then print out the line, which by default is called a record, denoted by $0. At least read up the documentation. If you only want to get print out the matched word. awk ‘{for(i=1;i<=NF;i++){ if($i==”yyy”){print $i} … Read more