The function you gave does not satisfy the challenge. Right shifting will not do what is asked for. For example, your notNotNot(6,true) is false, not true when put through your function.
Your question is about bitwise operation on a boolean though. Since operators like >> and << work on integers, Javascript first converts the boolean value to an integer. So true becomes 1 and false becomes 0. To see this you can shift by zero:
console.log("true is",true >> 0)
console.log("false is", false >> 0)So bitwise operation on booleans is really just bitwise operation on either 0 or 1.
Using !! is a handy way to convert anything into a boolean. It takes anything that would be considered equivalent to false (such as 0, null, undefined or “”) and gives back false. Similarly anything that is truthy (like 14, “hello”, [4], {a:1}) and give back true. !! works because the first exclamation mark gives the ‘not’ of the expression which is always true or false, then the second exclamation mark gives the opposite of that (false or true).
Getting back to the challenge, it wants to apply the not-operator ‘a’ times and compare to the ‘b’ value. So something like this would work:
function notNotNot(a, b) { return !!(a%2 - b); }
console.log("notNotNot(1, true)",notNotNot(1, true));
console.log("notNotNot(2, false)",notNotNot(2, false));
console.log("notNotNot(6, true)",notNotNot(6, true));