Find Process Name by its Process ID [closed]

The basic one, ask tasklist to filter its output and only show the indicated process id information

tasklist /fi "pid eq 4444" 

To only get the process name, the line must be splitted

for /f "delims=," %%a in ('
    tasklist /fi "pid eq 4444" /nh /fo:csv
') do echo %%~a

In this case, the list of processes is retrieved without headers (/nh) in csv format (/fo:csv). The commas are used as token delimiters and the first token in the line is the image name

note: In some windows versions (one of them, my case, is the spanish windows xp version), the pid filter in the tasklist does not work. In this case, the filter over the list of processes must be done out of the command

for /f "delims=," %%a in ('
    tasklist /fo:csv /nh ^| findstr /b /r /c:"[^,]*,\"4444\","
') do echo %%~a

This will generate the task list and filter it searching for the process id in the second column of the csv output.

edited: alternatively, you can suppose what has been made by the team that translated the OS to spanish. I don’t know what can happen in other locales.

tasklist /fi "idp eq 4444"