Xpath expression to find values that start with
I think this xpath should work //id[starts-with(text(),’Annotations’)]
I think this xpath should work //id[starts-with(text(),’Annotations’)]
Recommendation: Never use the != operator to compare inequality where one or both arguments are node-sets. By definition the expression: $node-set != $value evaluates to true() exactly when there is at least one node in $node-set such that its string value is not equal to the string value of $value. Using this definition: $empty-nodeset != … Read more
You can use this xpath: //a[.=”Next.”]/preceding::a[1] If I were to diagram it out, using an X to represent the current location, it would look like this: ——————+——+—————— preceding-sibling | self | following-sibling ——————|——|—————— last() … 2 1 | X | 1 2 … last() ——————+——+——————
Try this: //foo/following-sibling::text()[1] (replace //foo/ with your current XPath expression. With this XML: <data> <foo>foo</foo> bar <baz>baz</baz> </data> it gives bar as output.
You could do it this way: ../node[not(text()) and preceding-sibling::node[@id][1][@id=’1′]] where ‘1’ is the id of the current node (generate the expression dynamically). The expression says: from the current context go to the parent select those child nodes that have no text and from all “preceding sibling nodes that have an id” the first one must … Read more
Use: /*/ITEM[starts-with(REVENUE_YEAR,’2552′)]/REGION Note: Unless your host language can’t handle element instance as result, do not use text nodes specially in mixed content data model. Do not start expressions with // operator when the schema is well known.
You need to learn about namespaces and how to define/register a namespace in your XPath engine so that you can then use the associated prefix for names in that registered namespace. There are plenty of questions in the xpath tag asking how to use names that are in a namespace — with good answers. Search … Read more
(“*”) gives all the child elements of the context node. So use: body.findElement(By.xpath(“*”));
Use the following: (//dl)[1] The parentheses are significant. You want the first node that results from //dl (not the set of dl elements that are the first child of their parent (which is what //dl[1] (no parens) returns)). This is easier to see when one realizes that // is shorthand for (i.e. expands fully to) … Read more
[Update] XMLQuire was originally recommended in this answer. It was a free XML editor for Windows with the SketchPath XPath Editor built in for XPath testing. XMLQuire has not been maintained for a few years and has now been retired. For XPath experimentation etc. XMLQuire’s author now recommends the XPath Notebook extension for Visual Studio … Read more