Remove all whitespaces in a file- Linux
Depending on your definition of whitespace, something like: tr -d ‘ \t\n\r\f’ <inputFile >outputFile would do the trick.
Depending on your definition of whitespace, something like: tr -d ‘ \t\n\r\f’ <inputFile >outputFile would do the trick.
I’ll take a stab at it: /^[a-z](?:_?[a-z0-9]+)*$/i Explained: / ^ # match beginning of string [a-z] # match a letter for the first char (?: # start non-capture group _? # match 0 or 1 ‘_’ [a-z0-9]+ # match a letter or number, 1 or more times )* # end non-capture group, match whole group … Read more
You can get quite far just using the strings package as strings.Fields does most of the work for you: package main import ( “fmt” “strings” ) func standardizeSpaces(s string) string { return strings.Join(strings.Fields(s), ” “) } func main() { tests := []string{” Hello, World ! “, “Hello,\tWorld ! “, ” \t\n\t Hello,\tWorld\n!\n\t”} for _, test … Read more
After playing around with this, I’m satisfied that what I said in the question is right. Each call to (?PARNO) gets a complete and separate set of the match variables that it discards at the end of its run. You can get all the things that matched in each sub pattern by using an array … Read more
It is possible to get it done via mod_rewrite but make sure mod_proxy is enabled in your Apache’s httpd.conf. Once that is done enable mod_rewrite and .htaccess through httpd.conf and then put this code in your .htaccess under DOCUMENT_ROOT directory: Options +FollowSymLinks -MultiViews RewriteEngine On RewriteBase / RewriteCond %{HTTP_HOST} ^(www\.)?mydomain\.be$ [NC] RewriteRule ^ http://www.mydomain.nl%{REQUEST_URI} [L,NE,P] … Read more
Hysterical Raisens Part of the answer may involve the origins of REs in practical computing. They were originally a theoretical concept from automata theory and formal language theory until Ken Thompson himself wrote a real implementation and used them in qed and ed(1). The original version had only the greedy syntax and so there wasn’t … Read more
I don’t know of a way to do it directly as part of a variable substitution, but you can do it as a command: [[ “$name” =~ ^”$HOME”(/|$) ]] && name=”~${name#$HOME}” Note that this doesn’t do exactly what you asked for: it replaces “/home/alice/” with “~/” rather than “~”. This is intentional, since there are … Read more
Couldn’t you just check to see if there are no matches? I don’t know what language you are using, but how about this pseudocode? if (!’Some String’.match(someRegularExpression)) // do something… If you can only change the regex, then the one you got from your link should work: /^((?!REGULAR_EXPRESSION_HERE).)*$/
Now witness the firepower of this fully ARMED and OPERATIONAL battle station! (I have worked too much on this answer and my brain has broken; There should be a badge for that.) In order to determine if two patterns intersect, I have created a recursive backtracking parser — when Kleene stars are encountered a new … Read more
Use the following regex replacement: Find: myObject\[(.*?)\] Replace: myObject.get($1) If the index is an integer, you may replace (.*?) with (\d+). The pair of unescaped parentheses creates a capturing group that we may reference from the replacement pattern using $ + Group ID. $1 will insert the index into the replacement result.