It depends if you want to work with the user afterwards or only check if one exists. If you want to use the user object if it exists: $user = User::where(’email’, ‘=’, Input::get(’email’))->first(); if ($user === null) { // user doesn’t exist } And if you only want to check if (User::where(’email’, ‘=’, Input::get(’email’))->count() > … Read more
After save, $data->id should be the last id inserted. $data->save(); $data->id; Can be used like this. return Response::json(array(‘success’ => true, ‘last_insert_id’ => $data->id), 200); For updated laravel version try this return response()->json(array(‘success’ => true, ‘last_insert_id’ => $data->id), 200);
Just to state the obvious for anyone viewing this discussion…. if you give any of your folders 777 permissions, you are allowing ANYONE to read, write and execute any file in that directory…. what this means is you have given ANYONE (any hacker or malicious person in the entire world) permission to upload ANY file, … Read more
Both would return true on Unix systems – in Unix everything is a file, including directories. But to test if that name is taken, you should check both. There might be a regular file named ‘foo’, which would prevent you from creating a directory name ‘foo’.
I’d probably do something like this: <?php class Student { public function __construct() { // allocate your stuff } public static function withID( $id ) { $instance = new self(); $instance->loadByID( $id ); return $instance; } public static function withRow( array $row ) { $instance = new self(); $instance->fill( $row ); return $instance; } protected … Read more
The short answer is: $milliseconds = floor(microtime(true) * 1000);
Expanding on someone else’s answer: <script> var myvar = <?php echo json_encode($myVarValue); ?>; </script> Using json_encode() requires: PHP 5.2.0 or greater $myVarValue encoded as UTF-8 (or US-ASCII, of course) Since UTF-8 supports full Unicode, it should be safe to convert on the fly. Note that because json_encode escapes forward slashes, even a string that contains … Read more
Sounds like there is something wrong with your configuration, here are a few things you can check: Make sure that PHP is installed and running correctly. This may sound silly, but you never know. An easy way to check is to run php -v from a command line and see if returns version information or … Read more
Try; $data = json_decode(file_get_contents(‘php://input’), true); print_r($data); echo $data[“operacion”]; From your json and your code, it looks like you have spelled the word operation correctly on your end, but it isn’t in the json. EDIT Maybe also worth trying to echo the json string from php://input. echo file_get_contents(‘php://input’);
Run composer with –no-scripts composer update –no-scripts This shall fix the issue. I tried this on Mac and Linux.