How to find maximum value from a Integer using stream in Java 8?

You may either convert the stream to IntStream: OptionalInt max = list.stream().mapToInt(Integer::intValue).max(); Or specify the natural order comparator: Optional<Integer> max = list.stream().max(Comparator.naturalOrder()); Or use reduce operation: Optional<Integer> max = list.stream().reduce(Integer::max); Or use collector: Optional<Integer> max = list.stream().collect(Collectors.maxBy(Comparator.naturalOrder())); Or use IntSummaryStatistics: int max = list.stream().collect(Collectors.summarizingInt(Integer::intValue)).getMax();

Difference between Java 8 streams and RxJava observables

Short answer All sequence/stream processing libs are offering very similar API for pipeline building. The differences are in API for handling multi-threading and composition of pipelines. Long answer RxJava is quite different from Stream. Of all JDK things, the closest to rx.Observable is perhaps java.util.stream.Collector Stream + CompletableFuture combo (which comes at a cost of … Read more

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