You do not need a regex for this. String.lastIndexOf will do.
var str="tro.lo.lo.lo.lo.lo.zip";
var i = str.lastIndexOf('.');
if (i != -1) {
str = str.substr(0, i) + "@2x" + str.substr(i);
}
See it in action.
Update: A regex solution, just for the fun of it:
str = str.replace(/\.(?=[^.]*$)/, "@2x.");
Matches a literal dot and then asserts ((?=) is positive lookahead) that no other character up to the end of the string is a dot. The replacement should include the one dot that was matched, unless you want to remove it.