Swift 5
Use compactMapValues
:
dictionary.compactMapValues { $0 }
compactMapValues
has been introduced in Swift 5. For more info see Swift proposal SE-0218.
Example with dictionary
let json = [
"FirstName": "Anvar",
"LastName": "Azizov",
"Website": nil,
"About": nil,
]
let result = json.compactMapValues { $0 }
print(result) // ["FirstName": "Anvar", "LastName": "Azizov"]
Example including JSON parsing
let jsonText = """
{
"FirstName": "Anvar",
"LastName": "Azizov",
"Website": null,
"About": null
}
"""
let data = jsonText.data(using: .utf8)!
let json = try? JSONSerialization.jsonObject(with: data, options: [])
if let json = json as? [String: Any?] {
let result = json.compactMapValues { $0 }
print(result) // ["FirstName": "Anvar", "LastName": "Azizov"]
}
Swift 4
I would do it by combining filter
with mapValues
:
dictionary.filter { $0.value != nil }.mapValues { $0! }
Examples
Use the above examples just replace let result
with
let result = json.filter { $0.value != nil }.mapValues { $0! }