I believe that you can can do this with relatively simple bit operations:
function stringToBytes ( str ) {
var ch, st, re = [];
for (var i = 0; i < str.length; i++ ) {
ch = str.charCodeAt(i); // get char
st = []; // set up "stack"
do {
st.push( ch & 0xFF ); // push byte to stack
ch = ch >> 8; // shift value down by 1 byte
}
while ( ch );
// add stack contents to result
// done because chars have "wrong" endianness
re = re.concat( st.reverse() );
}
// return an array of bytes
return re;
}
stringToBytes( "A\u1242B\u4123C" ); // [65, 18, 66, 66, 65, 35, 67]
It should be a simple matter to sum the output up by reading the byte array as if it were memory and adding it up into larger numbers:
function getIntAt ( arr, offs ) {
return (arr[offs+0] << 24) +
(arr[offs+1] << 16) +
(arr[offs+2] << 8) +
arr[offs+3];
}
function getWordAt ( arr, offs ) {
return (arr[offs+0] << 8) +
arr[offs+1];
}
'\\u' + getWordAt( stringToBytes( "A\u1242" ), 1 ).toString(16); // "1242"