In this case you can do

```
a.map(&1.method(:+))
```

But only because 1 + x is usually the same as x + 1.

Here is a discussion of this practice in a performance context.

In this case you can do

```
a.map(&1.method(:+))
```

But only because 1 + x is usually the same as x + 1.

Here is a discussion of this practice in a performance context.