In this case you can do
a.map(&1.method(:+))
But only because 1 + x is usually the same as x + 1.
Here is a discussion of this practice in a performance context.
In this case you can do
a.map(&1.method(:+))
But only because 1 + x is usually the same as x + 1.
Here is a discussion of this practice in a performance context.